A. \(\frac{5}{{15}} = \frac{9}{{27}};\frac{{15}}{5} = \frac{{ - 27}}{{ - 9}};\frac{5}{{ - 9}} = \frac{{15}}{{ - 27}};\frac{{ - 9}}{5} = \frac{{ - 27}}{{15}}\)
B. \(\frac{5}{{15}} = \frac{9}{{27}};\frac{{15}}{5} = \frac{{ - 27}}{{ - 9}};\frac{5}{{ - 9}} = \frac{{15}}{{ - 27}};\frac{{ - 9}}{5} = \frac{{ - 15}}{{27}}\)
C. \(\frac{15}{{5}} = \frac{9}{{27}};\frac{{15}}{5} = \frac{{ - 27}}{{ 9}}\)
D. \(\frac{15}{{5}} = \frac{9}{{27}};\frac{{15}}{5} = \frac{{ - 27}}{{ - 9}};\frac{5}{{ - 9}} = \frac{{15}}{{ - 27}};\frac{{ - 9}}{5} = \frac{{ - 15}}{{27}}\)
A
Ta có 5.(-27) = (-9).15 nên \(\frac{5}{{15}} = \frac{9}{{27}};\frac{{15}}{5} = \frac{{ - 27}}{{ - 9}};\frac{5}{{ - 9}} = \frac{{15}}{{ - 27}};\frac{{ - 9}}{5} = \frac{{ - 27}}{{15}}\)
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