Tính ​\(I=\frac{15}{34}+\frac{15}{17}+\frac{19}{34}-1 \frac{15}{17}+\frac{2}{3}\) ta được

* Hướng dẫn giải

Ta có

\(\begin{aligned} &I=\frac{15}{34}+\frac{15}{17}+\frac{19}{34}-1 \frac{15}{17}+\frac{2}{3}=\frac{15}{34}+\frac{15}{17}+\frac{19}{34}-\left(1+\frac{15}{17}\right)+\frac{2}{3} \\ &=\frac{15}{34}+\frac{15}{17}+\frac{19}{34}-1-\frac{15}{17}+\frac{2}{3}=\frac{15}{34}+\frac{19}{34}-1+\frac{2}{3} \\ &=\frac{34}{34}-1+\frac{2}{3}=1-1+\frac{2}{3}=\frac{2}{3} \end{aligned}\)