Tính: (-3/4)^3; (1/2)^5

* Hướng dẫn giải

Ta có:

$$\begin{gathered} {\left(\frac{-3}{4}\right)}^3=\frac{-3}{4}.\frac{-3}{4}.\frac{-3}{4}=\frac{(-3).(-3).(-3)}{4.4.4}=\frac{{(-3)}^3}{4^3} \\ {\left(\frac{1}{2}\right)}^5=\frac{1}{2}.\frac{1}{2}.\frac{1}{2}.\frac{1}{2}.\frac{1}{2}=\frac{1.1.1.1.1}{2.2.2.2.2}=\frac{1^5}{2^5} \\ Vậy {\left(\frac{{\displaystyle -3}}{{\displaystyle 4}}\right)}^3=\frac{{\displaystyle {(-3)}^3}}{{\displaystyle 4^3}}; {\left(\frac{1}{2}\right)}^5=\frac{1^5}{2^5} \end{gathered}$$