Tìm x, biết: a) (1,2)^3 . x = (1,2)^5; b) (2/3)^7 : x = (2/3)^6

a) (1,2)³ . x = (1,2)⁵;

x = (1,2)⁵ : (1,2)³

x = (1,2)^{5 – 3}

x = (1,2)²

x = 1,44.

Vậy x = 1,44.

$$\begin{gathered} b) {\left(\frac{2}{3}\right)}^7:x={\left(\frac{2}{3}\right)}^6 \\ x={\left(\frac{2}{3}\right)}^7:{\left(\frac{2}{3}\right)}^6 \\ x={\left(\frac{2}{3}\right)}^{7-6} \\ x=\frac{2}{3} \\ Vậy x=\frac{2}{3} \end{gathered}$$