Bỏ dấu ngoặc rồi tính các tổng sau

a) $\frac{17}{11}-\left(\frac{6}{5}-\frac{16}{11}\right)+\frac{26}{5}$

$=\frac{17}{11}-\frac{6}{5}+\frac{16}{11}+\frac{26}{5}$

$=\frac{17}{11}+\frac{16}{11}+\frac{26}{5}-\frac{6}{5}$

$=\left(\frac{17}{11}+\frac{16}{11}\right)+\left(\frac{26}{5}-\frac{6}{5}\right)$

$=\frac{33}{11}+\frac{20}{5}$

$=3+4$

$=7$

b) $\frac{39}{5}+\left(\frac{9}{4}-\frac{9}{5}\right)-\left(\frac{5}{4}+\frac{6}{7}\right)$

$=\frac{39}{5}+\frac{9}{4}-\frac{9}{5}-\frac{5}{4}-\frac{6}{7}$

$=\frac{39}{5}-\frac{9}{5}+\frac{9}{4}-\frac{5}{4}-\frac{6}{7}$

$=\left(\frac{39}{5}-\frac{9}{5}\right)+\left(\frac{9}{4}-\frac{5}{4}\right)-\frac{6}{7}$

$=\left(\frac{39}{5}-\frac{9}{5}\right)+\left(\frac{9}{4}-\frac{5}{4}\right)-\frac{6}{7}$

$=\frac{30}{5}+\frac{4}{4}-\frac{6}{7}$

$=6+1-\frac{6}{7}$

$=7-\frac{6}{7}$

$=\frac{49}{7}-\frac{6}{7}$

$=\frac{43}{7}$