Thay dấu hỏi bằng dấu (lớn hơn, nhỏ hơn, bằng) thích hợp.

* Hướng dẫn giải

 $$\begin{gathered} a) \left(\frac{-5}{8}\right)+\left(\frac{3}{-8}\right)=\left(\frac{-5}{8}\right)+\left(\frac{-3}{8}\right)=\frac{-8}{8}=-1 \\ Vậy ta điền \left(\frac{-5}{8}\right)+\left(\frac{3}{-8}\right)\boxed{=}-1 \end{gathered}$$

$$\begin{gathered} b) \left(\frac{-13}{22}\right)+\left(\frac{-5}{22}\right)=\frac{-18}{22}=\frac{-9}{11}<\frac{-8}{11} \\ Vậy ta điền \left(\frac{-13}{22}\right)+\left(\frac{-5}{22}\right)\boxed{<}\frac{-8}{11} \end{gathered}$$

$$\begin{gathered} c) \frac{1}{6}+\left(\frac{-3}{4}\right)=\frac{2}{12}+\left(\frac{-9}{12}\right)=\frac{-7}{12} \\ \frac{1}{14}+\left(\frac{-4}{7}\right)=\frac{1}{14}+\left(\frac{-8}{14}\right)=\frac{-7}{14} \\ Ta có \frac{-7}{12}<\frac{-7}{14} \\ Vậy ta điền \frac{1}{6}+\left(\frac{-3}{4}\right)\boxed{<} \frac{1}{14}+\left(\frac{-4}{7}\right). \end{gathered}$$