Tính: (-2/3)^3; (-3/5)^2; (-0,5)^3; (-0,5)^2; (37,57)^0; (3,57)^1

* Hướng dẫn giải

$$\begin{gathered} {\left(\frac{-2}{3}\right)}^3=\frac{{\left(-2\right)}^3}{3^3}=\frac{-8}{27} \\ {\left(\frac{-3}{5}\right)}^2=\frac{{\left(-3\right)}^2}{5^2}=\frac{9}{25} \\ {\left(-0,5\right)}^3={\left(\frac{-1}{2}\right)}^3=\frac{{\left(-1\right)}^3}{2^3}=\frac{-1}{8} \\ {\left(-0,5\right)}^2={\left(\frac{-1}{2}\right)}^2=\frac{{\left(-1\right)}^2}{2^2}=\frac{1}{4} \\ {\left(37,57\right)}^0=1 \\ {\left(3,57\right)}^1=3,57 \end{gathered}$$