A. A < 2
B. A > 2
C. A < 1
D. A < 0
Đáp án đúng là: B
Ta có: \(A{\rm{ = }}\frac{1}{5}{\rm{ }} - {\rm{ }}\left[ {\left( {\frac{{ - {\rm{ 2}}}}{3}} \right){\rm{ }} - {\rm{ }}\left( {\frac{1}{3}{\rm{ + }}\frac{5}{6}} \right)} \right]\)
\( = {\rm{ }}\frac{1}{5}{\rm{ }} - {\rm{ }}\left[ {\left( {\frac{{ - {\rm{ 2}}}}{3}} \right){\rm{ }} - {\rm{ }}\left( {\frac{2}{6}{\rm{ + }}\frac{5}{6}} \right)} \right]\)
\( = {\rm{ }}\frac{1}{5}{\rm{ }} - {\rm{ }}\left( {\frac{{ - {\rm{ 2}}}}{3}{\rm{ }} - {\rm{ }}\frac{7}{6}} \right)\)
\( = {\rm{ }}\frac{1}{5}{\rm{ }} - {\rm{ }}\left( {\frac{{ - {\rm{ 4}}}}{6}{\rm{ }} - {\rm{ }}\frac{7}{6}} \right)\)
\( = {\rm{ }}\frac{1}{5}{\rm{ }} - {\rm{ }}\frac{{ - {\rm{ 11}}}}{6}\)
\( = {\rm{ }}\frac{6}{{30}}{\rm{ }} - {\rm{ }}\frac{{ - {\rm{ 55}}}}{{30}}\)
\( = {\rm{ }}\frac{{6{\rm{ }} - {\rm{ }}\left( { - {\rm{ 55}}} \right)}}{{30}}\)
\( = {\rm{ }}\frac{{61}}{{30}}.\)
Do \(A{\rm{ }} = {\rm{ }}\frac{{61}}{{30}}{\rm{ }} > {\rm{ }}\frac{{60}}{{30}}{\rm{ }} = {\rm{ }}2\) nên A > 2.
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