Tính A=[ (1/81-3/162). 81/17+35/34]: [(9/51+7/102).102/5+2017]

$A=\left[\left(\frac{1}{81}-\frac{3}{162}\right).\frac{81}{17}+\frac{35}{34}\right]:\left[\left(\frac{9}{51}+\frac{7}{102}\right).\frac{102}{5}+2017\right]$

$A=\left[\left(\frac{2}{162}-\frac{3}{162}\right).\frac{81}{17}+\frac{35}{34}\right]:\left[\left(\frac{18}{102}+\frac{7}{102}\right).\frac{102}{5}+2017\right]$

$A=\left[\frac{-1}{162}.\frac{81}{17}+\frac{35}{34}\right]:\left[\frac{25}{102}.\frac{102}{5}+2017\right]$

$A=\left[\frac{\left(-1\right).81}{162.17}+\frac{35}{34}\right]:\left[\frac{25.102}{102.5}+2017\right]$

$A=\left[\frac{-1}{34}+\frac{35}{34}\right]:\left[5+2017\right]$

$A=\frac{34}{34}:\left[5+2017\right]=1:2022=\frac{1}{2022}$