Thực hiện phép tính. b) (4^3 . 25^5 . 9^3) / (8^2 . 125^3 . 3^5)

b) $\frac{4^3.{25}^5.9^3}{8^2.{125}^3.3^5}=\frac{{\left(2^2\right)}^3.{\left(5^2\right)}^5.{\left(3^2\right)}^3}{{\left(2^3\right)}^2.{\left(5^3\right)}^3.3^5}$

$=\frac{2^6.5^{10}.3^6}{2^6.5^9.3^5}=5.3=15$