Thực hiện phép tính. c) 6 3 + 3 . 6 2 + 3 3 − 13

c) $\frac{6^3+3.6^2+3^3}{-13}=\frac{{(2.3)}^3+3.{(3.2)}^2+3^3}{-13}$

$=\frac{2^3.3^3+3.3^2.2^2+3^3}{-13}$

$=\frac{3^3(2^3+2^2+1)}{-13}=\frac{13.3^3}{-13}=-3^3=-27$