Tính c_ ( 3/5)^15 : (27/125) ^5 = (3/5)^15 : [(3/5)^3] ^5

c) ${\left(\frac{3}{5}\right)}^{15}:{\left(\frac{27}{125}\right)}^5={\left(\frac{3}{5}\right)}^{15}:{\left[{\left(\frac{3}{5}\right)}^3\right]}^5$

$={\left(\frac{3}{5}\right)}^{15}:{\left(\frac{3}{5}\right)}^{3.5}={\left(\frac{3}{5}\right)}^{15}:{\left(\frac{3}{5}\right)}^{15}=1$