Tính: c) 0 , 275 + ( − 8/17 ) + 29/40 + ( − 9/17 ) − 1(1/3) ;

c) $0,275+\left(\frac{-8}{17}\right)+\frac{29}{40}+\left(\frac{-9}{17}\right)-1\frac{1}{3}$

$=\frac{11}{40}+\left(\frac{-8}{17}\right)+\frac{29}{40}+\left(\frac{-9}{17}\right)-\frac{4}{3}$

$=(\frac{11}{40}+\frac{29}{40})+[\left(\frac{-8}{17}\right)+\left(\frac{-9}{17}\right)]-\frac{4}{3}$

$=1+(-1)-\frac{4}{3}=\frac{-4}{3}$