Thay dấu ? bằng dấu >, <, = thích hợp.

b) Ta có: $\left(\frac{-13}{33}\right)+\left(\frac{-14}{33}\right)=\frac{-27}{33}=\frac{-9}{11}$

Vì −9 > −10 nên $\frac{-9}{11}>\frac{-10}{11}$ .

Vậy $\left(\frac{-13}{33}\right)+\left(\frac{-14}{33}\right)\boxed{>}\left(\frac{-10}{11}\right)$ ;