Tính (1 3/4)^3-(1 3/4)^2+(-1.031)^0

* Hướng dẫn giải

${\left(1\frac{3}{4}\right)}^3-{\left(1\frac{3}{4}\right)}^2+{\left(-\mathrm{1,031}\right)}^0={\left(1\frac{3}{4}\right)}^2\left(1\frac{3}{4}-1\right)+1={\left(\frac{7}{4}\right)}^2\left(\frac{7}{4}-1\right)+1=\frac{49}{16}.\frac{3}{4}+1=\frac{211}{64}$