Tính: a) P = 1 – 2 + 2^2 – 2^3 +...+ 2^2022;

a) P = 1 – 2 + 2² – 2³ +...+ 2²⁰²²

2P = 2 – 2² + 2³ – 2⁴ +...+ 2²⁰²³

Suy ra P + 2P = (1 – 2 + 2² – 2³ +...+ 2²⁰²²) + (2 – 2² + 2³ – 2⁴ +...+ 2²⁰²³)

Hay 3P = 1 + (–2 + 2) + (2² – 2²) + (–2³ + 2³) +...+ (2²⁰²² – 2²⁰²²) + 2²⁰²³

3P = 1 + 0 + 0 + 0 +...+ 0 + 2²⁰²³

3P = 1 + 2²⁰²³

$P=\frac{1+2^{2023}}{3}$

Vậy $P=\frac{1+2^{2023}}{3}$.