Tìm x |x+1/3|-5=6

* Hướng dẫn giải

${\left(\frac{1}{2}\right)}^{x+1}-\frac{1}{2}=-\frac{3}{8}$

${\left(\frac{1}{2}\right)}^{x+1}=-\frac{3}{8}+\frac{1}{2}$

${\left(\frac{1}{2}\right)}^{x+1}=\frac{1}{8}$

${\left(\frac{1}{2}\right)}^{x+1}={\left(\frac{1}{2}\right)}^3$

$x+1=3$

$x=2$

Vậy $x=2$