b) 2: ( 1/2 - 2/3) ^2+ 0,125^3. 8^ 3- ( -12)^4: 6^4.

* Hướng dẫn giải

b) $2:{\left(\frac{1}{2}-\frac{2}{3}\right)}^2+0,{125}^3{.8}^3-{\left(-12\right)}^4:6^4$

$=2:{\left(\frac{3}{6}-\frac{4}{6}\right)}^2+{\left(0,125.8\right)}^3-\frac{{\left(-12\right)}^4}{6^4}$

$=2:{\left(\frac{-1}{6}\right)}^2+{\left(1\right)}^3-\frac{{12}^4}{6^4}$

$=2:\frac{{\left(-1\right)}^2}{6^2}+1-{\left(\frac{12}{6}\right)}^4$

$=2:\frac{1}{6^2}+1-2^4$

= 2.6² + 1 – 2⁴

= 2.36 + 1 – 16

= 72 + 1 – 16

= 57