Tính B= 8^5+ 4^6/ 2^ 15+ 64^3

* Hướng dẫn giải

$B=\frac{{\left(2^3\right)}^5+{\left(2^2\right)}^6}{2^{15}+{\left(2^6\right)}^3}=\frac{2^{15}+2^{12}}{2^{15}+2^{18}}=\frac{2^{12}.\left(2^3+1\right)}{2^{15}.\left(1+2^3\right)}=\frac{1}{2^3}=\frac{1}{8}$