Để sản xuất 29,7 kg xenlulozơ trinitrat (hiệu suất 90%) bằng phản ứng giữa

Đáp án A.

$$\begin{gathered} {\left[C_6{H}_7{O}_2{\left(OH\right)}_3\right]}_n+3nHN{O}_3\stackrel{H_{2}S{O}_4}{\to }{\left[C_6{H}_7{O}_2{\left(ON{O}_2\right)}_3\right]}_n+3n{H}_{2}O \\ {n}_{HN{O}_3\left(phanung\right)}=3n.n_{xenlulozotrinitrat}=3n.\frac{m_{xenlulozotrinitrat}}{297n}=3n.\frac{29,7.1000}{297n}=300mol \\ {m}_{HN{O}_3\left(dadung\right)}=\frac{m_{HN{O}_{3\left(phanung\right)}}}{H\%}=\frac{300.63}{90\%}=21000gam \\ {m}_{dd}=\frac{m_{HN{O}_3\left(dadung\right)}}{C\%}=\frac{21000}{60\%}=35000gam=35\left(kg\right) \end{gathered}$$