Cho hàm số f ( x ) = ( a x + b )^5 (với a,b là tham số). Tính f ( 10 ) (1)

\[\begin{array}{*{20}{l}}{f'\left( x \right) = 5a{{\left( {ax + b} \right)}^4}}\\{f''\left( x \right) = 20{a^2}{{\left( {ax + b} \right)}^3}}\\{f'''\left( x \right) = 60{a^3}{{\left( {ax + b} \right)}^2}}\\{{f^{\left( 4 \right)}}\left( x \right) = 120{a^4}\left( {ax + b} \right)}\\{{f^{\left( 5 \right)}}\left( x \right) = 120{a^5}}\\{{f^{\left( 6 \right)}}\left( x \right) = 0}\\{ \Rightarrow {f^{\left( {10} \right)}}\left( x \right) = 0\,\,\forall x \in R \Rightarrow {f^{\left( {10} \right)}}\left( 1 \right) = 0}\end{array}\]