Cho tam giác ABC có (widehat B = {80^0};3widehat A = 2widehat C). Tính (widehat A;widehat C)?

A. \(\widehat A = {60^0};\widehat C = {40^0}\)

B. \(\widehat A = {30^0};\widehat C = {50^0}\)

C. \(\widehat A = {40^0};\widehat C = {60^0}\)

D. \(\widehat A = {40^0};\widehat C = {30^0}\)