Em tham khảo nha:

\(\begin{array}{l}
1)\\
a)\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
nZn = \dfrac{{13}}{{65}} = 0,2\,mol\\
\dfrac{{0,2}}{1} > \dfrac{{0,3}}{2} \Rightarrow \text{ Zn dư} \\
nZn = 0,2 - 0,15 = 0,05\,mol\\
mZn = 0,05 \times 65 = 3,25g\\
b)\\
n{H_2} = 0,15\,mol \Rightarrow V{H_2} = 0,15 \times 22,4 = 3,36l\\
2)\\
nFe = \dfrac{{11,2}}{{56}} = 0,2\,mol\\
nCuS{O_4} = \dfrac{{40}}{{160}} = 0,25\,mol\\
\dfrac{{0,2}}{1} < \dfrac{{0,25}}{1} \Rightarrow \text{CuSO_4 dư} \\
nCu = nFe = 0,2\,mol\\
mCu = 0,2 \times 64 = 12,8g\\
3)\\
a)\\
nFe = \dfrac{{22,4}}{{56}} = 0,4\,mol\\
n{H_2}S{O_4} = \dfrac{{24,5}}{{98}} = 0,25\,mol\\
\dfrac{{0,4}}{1} > \dfrac{{0,25}}{1} \Rightarrow\text{ Fe dư} \\
n{H_2} = n{H_2}S{O_4} = 0,25\,mol\\
V{H_2} = 0,25 \times 22,4 = 5,6l\\
b)\\
nFe = 0,4 - 0,25 = 0,15\,mol\\
mFe = 0,15 \times 56 = 8,4g\\
nFeS{O_4} = n{H_2}S{O_4} = 0,25\,mol\\
mFeS{O_4} = 0,25 \times 152 = 38g
\end{array}\)