Đáp án:

 $a) -\dfrac{1}{2}+\dfrac{5}{6}+\dfrac{1}{3}$

$= (-\dfrac{3}{6})+\dfrac{5}{6}+ \dfrac{2}{3}$

$= \dfrac{(-3)+5+2}{6}$

$= \dfrac{4}{6}$

$= \dfrac{2}{3}$

$b) -\dfrac{3}{8}+\dfrac{7}{4}-\dfrac{1}{12}$

$= (-\dfrac{9}{24})+\dfrac{42}{24}-\dfrac{2}{24}$

$= \dfrac{(-9)+42-2}{24}$

$= \dfrac{31}{24}$

$c) \dfrac{3}{5}:(\dfrac{1}{4}-\dfrac{7}{5})$

$= \dfrac{3}{5}:(\dfrac{5}{20}-\dfrac{28}{20})$

$= \dfrac{3}{5}:-\dfrac{23}{20}$

$= \dfrac{3}{5}.\dfrac{20}{-23}$

$= -\dfrac{12}{23}$

$d) \dfrac{10}{11}+\dfrac{4}{11}:4-\dfrac{1}{8}$

$= \dfrac{10}{11}+(\dfrac{4}{11}.\dfrac{1}{4})-\dfrac{1}{8}$

$= \dfrac{10}{11}+\dfrac{1}{11}-\dfrac{1}{8}$

$= \dfrac{11}{11}-\dfrac{1}{8}$

$= 1-\dfrac{1}{8}$

$= \dfrac{8}{8}-\dfrac{1}{8}$

$=\dfrac{7}{8}$

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