Bài 10:

a.

$2C{H_4}\xrightarrow[{làm\,\,lạnh\,\,nhanh}]{{{{1500}^o}C}}{C_2}{H_2} + 3{H_2}$

${C_2}{H_2} + {H_2}\xrightarrow{{Pd/PbC{O_3}}}{C_2}{H_4}$

${C_2}{H_4} + {H_2}O \to {C_2}{H_5}OH$

${C_2}{H_5}OH\xrightarrow{{{H_2}S{O_4},\,\,{{170}^o}C}}{C_2}{H_4} + {H_2}O$

$nC{H_2} = C{H_2}\xrightarrow{{{t^o},\,\,xt}}{( - C{H_2} - C{H_2} - )_n}$

b.

$Ca{C_2} + 2{H_2}O \to Ca{(OH)_2} + {C_2}{H_2}$

$2CH \equiv CH \to CH \equiv C - CH = C{H_2}$

$CH \equiv C - CH = C{H_2} + {H_2}\xrightarrow{{Pd/PbC{O_3}}}C{H_2} = CH - CH = C{H_2}$

$nC{H_2} = CH - CH = C{H_2}\xrightarrow{{{t^o},xt,p}}{( - C{H_2} - CH = CH - C{H_2} - )_n}$

c.

$CH \equiv CH + 2AgN{O_3} + 2N{H_3} \to CAg \equiv CAg + 2N{H_4}N{O_3}$

$CAg \equiv CAg + 2HCl \to CH \equiv CH + 2AgCl$

$CH \equiv CH + {H_2}O \to C{H_3}CHO$

$C{H_3}CHO + {H_2}\xrightarrow{{Ni,\,\,{t^o}}}C{H_3}C{H_2}OH$

Câu 11:

* ${C_3}{H_4}$:

$CH \equiv C - C{H_3}$: propin

* ${C_4}{H_6}$:

$CH \equiv C - C{H_2} - C{H_3}$: but-1-in

$C{H_3} - C \equiv C - C{H_3}$: but-2-in

* ${C_5}{H_8}:$

$CH \equiv C - C{H_2} - C{H_2} - C{H_3}$: pent-1-in

$C{H_3} - C \equiv C - C{H_2} - C{H_3}$: pent-2 -in

$CH \equiv C - CH(C{H_3}) - C{H_3}$: 3 - metylbut-1-in

* $C_6H_{10}$:

$CH \equiv C - C{H_2} - C{H_2} - C{H_2} - C{H_3}$: hex-1-in

$C{H_3} - C \equiv C - C{H_2} - C{H_2} - C{H_3}$: hex-2-in

$C{H_3} - C{H_2} - C \equiv C - C{H_2} - C{H_3}$: hex-3-in

$CH \equiv C - C{H_2} - CH(C{H_3}) - C{H_3}$: 4-metyl-pent-1-in

$CH \equiv C - CH(C{H_3}) - C{H_2} - C{H_3}$: 3-metyl-pent-1-in

$C{H_3} - C \equiv C - CH(C{H_3}) - C{H_3}$: 4-metyl-pent-2-in

$CH \equiv C - C{(C{H_3})_2} - C{H_3}$: 3,3-đi metylbut-1-in