Đáp án:

 1/

$CH_{3}COONa+NaOH \to Na_{2}CO_{3}+CH_{4}$

$2CH_{4} \buildrel{{1500^oC, làm lạnh nhanh}}\over\longrightarrow C_{2}H_{2}+3H_{2}$

$C_{2}H_{2}+H_{2} \buildrel{{Pd,t^o}}\over\longrightarrow C_{2}H_{4}$

$C_{2}H_{4}+Br_{2} \to C_{2}H_{4}Br_{2}$

$CH_{4}+Cl_{2} \buildrel{{as}}\over\longrightarrow CH_{3}Cl+HCl$

$C_{2}H_{2} +H_{2} \buildrel{{t^o,Ni}}\over\longrightarrow C_{2}H_{6}$

$CH=CH \buildrel{{t^o,p,xt}}\over\longrightarrow -(CH-CH)-_{n}$

2/

$Al_{4}C_{3}+12H_{2}O \to 4Al(OH)_{3}+3CH_{4}$

$2CH_{4} \buildrel{{1500^oC, làm lạnh nhanh}}\over\longrightarrow C_{2}H_{2}+3H_{2}$

$CH=CH \buildrel{{t^o,p,xt}}\over\longrightarrow -(CH-CH)-_{n}$

$C_{2}H_{4}+3O_{2} \buildrel{{t^o}}\over\longrightarrow 2CO_{2}+2H_{2}O$

Giải thích các bước giải: