$CH_4+Cl_2\buildrel{{as}}\over\to CH_3Cl+HCl$

$C_2H_4+Br_2\to C_2H_4Br_2$

$C_2H_4+3O_2\buildrel{{t^o}}\over\to 2CO_2+2H_2O$

$CH_3COOH+NaOH\to CH_3COONa+H_2O$

$2C_2H_5OH+2Na\to 2C_2H_5ONa+H_2$

$CH_3COOH+KOH\to CH_3COOK+H_2O$

$CH_4+2O_2\buildrel{{t^o}}\over\to CO_2+2H_2O$

$2CH_3COOH+Na_2O\to 2CH_3COONa+H_2O$

$2CH_3COOH+CaO\to (CH_3COO)_2Ca+H_2O$

$2CH_3COOH+K_2O\to 2CH_3COOK+H_2O$

$CH_3COOH+C_2H_5OH\buildrel{{t^o, H_2SO_4}}\over\rightleftharpoons CH_3COOC_2H_5+H_2O$

Đáp án:

Giải thích các bước giải:

 a)  CH₄ + Cl₂ ---as--> CH₃Cl + HCl

 b)  C₂H₄ + Br₂-----> CH₂Br + CH₂Br

 c)  C₂H₄ + 3O₂ ---t°---> 2CO₂ + 2H₂O

 d)CH₃COOH+NaOH --->CH₃COONa+H₂O

 e)  2C₂H₅OH +2 Na ----> 2C₂H₅ONa + H₂↑

 f)CH₃COOH+KOH ----> CH₃COOK + H₂O

 g)  CH₄ + 2O₂ -----t°--> CO₂ + 2H₂O

h 2CH₃COOH+Na₂O--->2CH₂COONa+H₂O

i2CH₃COOH+CaO --->(CH₃COO)₂Ca+H₂O

k)2CH₃COOH+K₂O --> 2CH₃COOK + H₂O

l)  CH₃COOH + C₂H₅OH ⇄CH₃COOC₂H₅+H₂O