Đáp án:

( $3$$\frac{1}{2}$ - $2x$) . $3$$\frac{2}{3}$ = $5$$\frac{1}{3}$ 

( $\frac{7}{2}$ - $2x$ ) . $\frac{11}{3}$ = $\frac{16}{3}$ 

$\frac{7}{2}$ - $2x$ = $\frac{16}{3}$ : $\frac{11}{3}$

$\frac{7}{2}$ - $2x$ = $\frac{16}{11}$

$2x$ = $\frac{7}{2}$ - $\frac{16}{11}$

$2x$ = $\frac{77}{22}$ - $\frac{32}{22}$

$2x$ = $\frac{45}{22}$ 

$x$ = $\frac{45}{22}$ : $2$

$x$ = $\frac{45}{44}$ 

Vậy x = $\frac{45}{44}$ 

Mai thi tốt nha

$c$) $(3\dfrac{1}{2} - 2x) . 3\dfrac{2}{3} = 5\dfrac{1}{3}$

$⇔ (\dfrac{7}{2} - 2x) . \dfrac{11}{3} = \dfrac{16}{3}$

$⇔ \dfrac{7}{2} - 2x = \dfrac{16}{3} : \dfrac{11}{3}$

$⇔ \dfrac{7}{2} - 2x = \dfrac{16.3}{3.11}$

$⇔ \dfrac{7}{2} - 2x = \dfrac{16}{11}$

$⇔ 2x = \dfrac{7}{2} - \dfrac{16}{11}$

$⇔ 2x = \dfrac{45}{22}$

$⇔ x = \dfrac{45}{22} : 2$

$⇔ x = \dfrac{45}{22.2}$

$⇔ x = \dfrac{45}{44}$

 Vậy $ x = \dfrac{45}{44}$.