Đáp án:

 

Giải thích các bước giải:

$(1)CaC_2+2H_2O\to C_2H_2+Ca(OH)_2$

$(2)2CH_4\xrightarrow[LLN]{1500^oC}C_2H_2+3H_2$

$(3)C_2H_2+HCl\xrightarrow[HgCl_2]{t^o}CH_2=CH-Cl$

$(5)nCH_2=CH-Cl\xrightarrow{t^o,p,xt}(\kern-6pt- CH_2-CH-Cl -\kern-6pt)_n$

$(6)C_2H_2+2H_2\xrightarrow[Ni]{t^o}C_2H_6$

$(7)C_2H_6+Cl_2\xrightarrow{ánh\, sáng}C_2H_5Cl+HCl$

$(8)C_2H_4+H_2O\xrightarrow{t^o,H_2SO_4}C_2H_5OH$

$(9)C_2H_4+H_2\xrightarrow[Ni]{t^o}C_2H_6$

$(10)C_2H_2+H_2\xrightarrow{t^o,Pd}C_2H_4$

$(11)2C_2H_2\xrightarrow{t^o,p,xt}CH\equiv C-CH=CH_2$

$(12)CH\equiv C-CH=CH_2+H_2\xrightarrow{t^o,Pd/PbCO_3}CH_2=CH-CH=CH_2$

$(13)nCH_2=CH-CH=CH_2\xrightarrow{t^o,p,xt}(\kern-6pt- CH_2-CH=CH-CH_2 -\kern-6pt)_n$

$(14)C_2H_5OH\xrightarrow{170^oC,H_2SO_4}C_2H_4+H_2O$

$(15)nCH_2=CH_2\xrightarrow{t^o,p,xt}(\kern-6pt- CH_2-CH_2 -\kern-6pt)_n$

$(16)C_2H_4+HCl\xrightarrow{ánh\, sáng}C_2H_5Cl$

$\text{Đáp án:}$
$\text{Trong hình}$
$\color{Red}{\text{#blackwolf4869}}$