Giải thích các bước giải:

Câu 1:

1)

\({H_3}P{O_4}\): Axit photphoric

\({P_2}{O_5}\): Photpho pentaoxit

\(Mg{(OH)_2}\): Magie hidroxit

\(NaN{O_3}\): Natri nitrat

2) 

- Bazo: \(Mg{(OH)_2}\)

- Axit: \({H_3}P{O_4}\)

- Oxit: \({P_2}{O_5}\)

- Muối: \(NaN{O_3}\)

Câu 3:

\(\begin{array}{l}
1.\\
F{e_2}{O_3} + 3CO \to 2Fe + 3C{O_2}\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
FeC{l_2} + 2NaOH \to Fe{(OH)_2} + 2NaCl\\
Fe{(OH)_2} + {H_2}S{O_4} \to FeS{O_4} + 2{H_2}O\\
2.\\
a)2Al + 3C{l_2} \to 2AlC{l_3}\\
b)2Al + 3C{\rm{uS}}{O_4} \to A{l_2}{(S{O_4})_3} + 3Cu
\end{array}\)

Câu 5:

\(\begin{array}{l}
1)\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
ZnO + 2HCl \to ZnC{l_2} + {H_2}O\\
2)\\
{n_{{H_2}}} = 0,1mol\\
 \to {n_{Zn}} = {n_{{H_2}}} = 0,1mol\\
 \to {m_{Zn}} = 6,5g\\
 \to {m_{ZnO}} = 14,6 - 6,5 = 8,1g\\
 \to {n_{ZnO}} = 0,1mol\\
3)\\
{n_{HCl}} = 2{n_{Zn}} + 2{n_{ZnO}} = 0,4mol\\
 \to {m_{HCl}} = 14,6g\\
 \to {m_{{\rm{dd}}HCl}} = \dfrac{{14,6}}{{7,3\% }} \times 100\%  = 200g
\end{array}\)