Đáp án:

 

Giải thích các bước giải:

$a/$

$A_1 : CH_2=C(CH_3)-COOH$

$A_2 : CH_3OH$

$A : CH_2=C(CH_3)-COOCH_3$

Phương trình hóa học :

$CH_2=C(CH_3)-COOH + CH_3OH \buildrel{{xt}}\over\rightleftharpoons CH_2=C(CH_3)-COOCH_3 + H_2O$

$nCH_2=C(COOCH_3)(CH_3) \xrightarrow{t^o,xt,p} (-CH_2-C(COOCH_3)(CH_3)-)_n$

$2CH_2=C(CH_3)-COOH + CaCO_3 → (CH_2=C(CH_3)-COO)_2Ca + CO_2 + H_2O$

$2CH_2=C(CH_3)-COOH + 2Na → 2CH_2=C(CH_3)-COONa + H_2$

$2CH_3OH + 2Na → CH_3ONa + H_2$

$b/$

$CH_2=C(CH_3)-COOCH_3 + H_2 \xrightarrow{t^o,xt} CH_3-CH(CH_3)-COOCH_3$
$CH_2=C(CH_3)-COOCH_3 + HBr \xrightarrow{t^o} CH_3-CBr(CH_3)-COOCH_3$

$CH_2=C(CH_3)-COOCH_3 + NaOH → CH_2=C(CH_3)-COONa + CH_3OH$

$CH_2=C(CH_3)-COOCH_3 + Br_2 → CH_2Br-CBr(CH_3)-COOCH_3 $

 

a,

$A:CH_2=C(CH_3)-COOCH_3$ (metyl metaacrylat)

$A_1: CH_2=C(CH_3)-COOH$ (axit metaacrylic) 

$A_2: CH_3OH$ (metanol)

$nCH_2=C(CH_3)-COOCH_3\buildrel{{t^o, p, xt}}\over\to (-CH_2-C(CH_3)(COOCH_3-)_n$

$2CH_2=C(CH_3)-COOH+CaCO_3\to (CH_2=C(CH_3)-COO)_2Ca+CO_2+H_2O$

$2CH_2=C(CH_3)-COOH+2Na\to 2CH_2=C(CH_3)COONa+H_2$

$2CH_3OH+2Na\to 2CH_3ONa$

b,

$CH_2=C(CH_3)-COOCH_3+H_2\buildrel{{Ni, t^o}}\over\to CH_3-CH(CH_3)-COOCH_3$

$CH_2=C(CH_3)-COOCH_3+HBr\to CH_3-CBr(CH_3)-COOCH_3$ (spc)

$CH_2=C(CH_3)-COOCH_3+NaOH\buildrel{{t^o}}\over\to CH_2=C(CH_3)-COONa+CH_3OH$

$CH_2=C(CH_3)-COOCH_3+Br_2\to CH_2Br-CBr(CH_3)-COOCH_3$