Em tham khảo nha:

\(\begin{array}{l}
c)\\
MXY{Z_4} = 207 + 26 = 233\\
MZ = \dfrac{{64}}{4} = 16({\rm{d}}vC) \Rightarrow Z:{\rm{Ox}}i(O)\\
MY = 2MZ = 32(dVC) \Rightarrow Y:S\\
MX + MY + 4MZ = 233 \Rightarrow MX = 137(dVC) \Rightarrow X:Ba\\
 \Rightarrow CTHH:BaS{O_4}\\
d)\\
MXY{O_4} = 2 \times 80 = 160(dvC)\\
MX + MY + 16 \times 4 = 160\\
 \Rightarrow 3MY = 96 \Rightarrow MY = 32(dvC) \Rightarrow Y:S\\
MX = 32 \times 2 = 64(dvC) \Rightarrow X:Cu\\
 \Rightarrow CTHH:CuS{O_4}\\
e)\\
MXY{O_3} = 108 + 9 = 116(dvC)\\
MX + MY + 16 \times 3 = 116\\
 \Rightarrow \dfrac{{14MY}}{3} + MY + 48 = 116 \Rightarrow MY = 12(dVC) \Rightarrow Y:C\\
 \Rightarrow MX = \dfrac{{14}}{3} \times 12 = 56(dVC) \Rightarrow X:Fe\\
 \Rightarrow CTHH:FeC{O_3}
\end{array}\)

Đáp án:

Giải thích các bước giải: