Em tham khảo nha:

\(\begin{array}{l}
17)\\
a)\\
CuO + CO \to Cu + C{O_2}\\
F{e_2}{O_3} + 3CO \to 2Fe + 3C{O_2}\\
C{O_2} + Ca{(OH)_2} \to CaC{O_3} + {H_2}O\\
A:Cu,Fe\\
B:C{O_2},CO\\
E:CO\\
b)\\
nC{O_2} = nCaC{O_3} = \dfrac{{50}}{{100}} = 0,5\,mol\\
hh:CuO(a\,mol),F{e_2}{O_3}(b\,mol)\\
80a + 160b = 32\\
a + 3b = 0,5\\
 \Rightarrow a = 0,2;b = 0,1\\
\% mCuO = \dfrac{{0,2 \times 80}}{{32}} \times 100\%  = 50\% \\
\% mF{e_2}{O_3} = 100 - 50 = 50\% \\
c)\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
nHCl = 2nFe = 0,4\,mol\\
a = {C_M}HCl = \dfrac{{0,4}}{{0,5}} = 0,8M\\
n{H_2} = nFe = 0,2\,mol \Rightarrow V{H_2} = 0,2 \times 22,4 = 4,48l\\
mZ = mCu = 0,2 \times 64 = 12,8g
\end{array}\)