Em tham khảo nha:

\(\begin{array}{l}
1)\\
NaOH + HCl \to NaCl + {H_2}O\\
nNaOH = \dfrac{{200 \times 10\% }}{{40}} = 0,5\,mol\\
nHCl = nNaOH = 0,5\,mol\\
m{\rm{dd}}HCl = \dfrac{{0,5 \times 36,5}}{{2,65\% }} = 688,68g\\
2)\\
{P_1}:\\
{H_2}S{O_4} + BaC{l_2} \to BaS{O_4} + 2HCl\\
{P_2}:\\
{H_2}S{O_4} + N{a_2}C{O_3} \to N{a_2}S{O_4} + C{O_2} + {H_2}O\\
2HCl + N{a_2}C{O_3} \to 2NaCl + C{O_2} + {H_2}O\\
nBaS{O_4} = n{H_2}S{O_4} = \dfrac{{6,99}}{{233}} = 0,03\,mol\\
nC{O_2} = \dfrac{{0,896}}{{22,4}} = 0,04\,mol\\
nHCl = (0,04 - 0,03) \times 2 = 0,02\,mol\\
{C_M}{H_2}S{O_4} = \dfrac{{0,03 \times 2}}{{0,01}} = 6M\\
{C_M}HCl = \dfrac{{0,02 \times 2}}{{0,01}} = 4M
\end{array}\)