a,x²+2x+1=(x+1)²

b,4x²-12x+9=(2x-3)²

c,9x²-4y²=(3x+2y)(3x-2y)

d,8x³-27=(2x-3)(4x²+6x+9)

e,16a²-(x-y)²=(4a+x-y)(4a-x+y)

f,(a-3b)²-16c²=(a-3b+4c)(a-3b-4c)

g,16(x-y)²-25(x+y)²=4²(x-y)²-5²(x+y)²=(4x-4y)²-(5x+5y)²=(4x-4y+5x+5y)(4x-4y-5x-5y)=(9x+y)(-x-9y)

h,m³-27=(m-3)(m²+3m+9)

i,8m³+6m²n+54mn²+27n³=(2m+3n)³

j,$\frac{1}{4}$$a^{2}$-$b^{2}$=($\frac{1}{2}a$)$^{2}$-$b^{2}$=($\frac{1}{2}a$+b)($\frac{1}{2}a$-b)

k,$a^{4}$-$b^{4}$=($a^{2}$)$^{2}$-($b^{2}$)$^{2}$=($a^{2}$+$b^{2}$)($a^{2}$-$b^{2}$)=($a^{2}$+$b^{2}$)(a+b)(a-b)

l,$1$+$\frac{1}{64}$$x^{3}$=$1$+($\frac{1}{4}x$)$^{3}$=($1$+$\frac{1}{4}$)($1$-$\frac{1}{4}x$+$\frac{1}{16}$$x^{2}$)

Đáp án:

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