`a,4x(x-32)=0`

`⇔` \(\left[ \begin{array}{l}4x=0\\x-32=0\end{array} \right.\) `⇔` \(\left[ \begin{array}{l}x=0\\x=32\end{array} \right.\) 

`b,(x-3)(x-8)=0`

`⇔` \(\left[ \begin{array}{l}x-3=0\\x-8=0\end{array} \right.\) `⇔` \(\left[ \begin{array}{l}x=3\\x=8\end{array} \right.\) 

`f,(2x-2).45=0`

`⇔2x-2=0`

`⇔2(x-1)=0`

`⇔x-1=0`

`⇔x=1`

`g,32(5x-8)=32`

`⇒5x-8=1`

`⇔5x=9`

`⇔x=9/5`

`h,(x-4)(x-7)=0`

`⇔` \(\left[ \begin{array}{l}x-4=0\\x-7=0\end{array} \right.\) `⇔` \(\left[ \begin{array}{l}x=4\\x=7\end{array} \right.\) 

`i,5x(3x-15)=0`

`⇔` \(\left[ \begin{array}{l}5x=0\\3x-15=0\end{array} \right.\) `⇔` \(\left[ \begin{array}{l}x=0\\x=5\end{array} \right.\)

`k,(2x-3)(x-2)=0`

`⇔` \(\left[ \begin{array}{l}2x-3=0\\x-2=0\end{array} \right.\) `⇔` \(\left[ \begin{array}{l}x=\dfrac{3}{2}\\x=2\end{array} \right.\)

Đáp án:

 

Giải thích các bước giải:

a)4x(x-32)=0

⇒4x=0 hay x-32=0

⇒x=0 hay x=32

vậy x=0 hay x=32

b)(x-3)(x-8)=0

⇒x-3 =0 hay x-8=0

⇒x=3 hay x=8

vậy x=3 hay x=8

f)(2x-2)45=0

⇒90x-90=0

⇒90x=90

⇒x=1

vậy x=1

g)32(5x-8)=32

⇒160x-256=32

⇒160x=32+256

⇒160x=288

⇒x=288/160

⇒x=1,8

vậy x=1,8

h)(x-4)(x-7)=0

⇒x-4=0 hay x-7=0

⇒x=4 hay x=7

vậy x=4 hay x=7

i)5x(3x-15)=0

⇒5x=0 hay 3x-15=0

⇒x=0 hay x=5

vậy x=0 hay x=5

k)(2x-3)(x-2)=0

⇒2x-3=0 hay x-2=0

⇒x=3/2 hay x=2