Đáp án:

` |x| = 0`

` => x =0`

*********

` |x| = 1,375`

` =>`

\(\left[ \begin{array}{l}x=1,375\\x=-1,375\end{array} \right.\)

*********

` |x| = 1/5`

` => `

\(\left[ \begin{array}{l}x=\dfrac{1}{5}\\x=\dfrac{-1}{5}\end{array} \right.\)

*********

` |x| = 3 1/4`

` => |x| = 13/4`

` =>`

\(\left[ \begin{array}{l}x=\dfrac{13}{4}\\x=\dfrac{-13}{4}\end{array} \right.\)

*********

` |x -1,5| = 2`

Trường hợp `1`

` x -1,5 = 2`

` => x= 2+1,5 = 3,5`

TH`2`

` x -1,5 = -2`

` x =-2 +1,5`

` x = -0,5`

*********

`| x +3/4| -1/2 = 0`

` |x+3/4| = 1/2`

TH1

` x +3/4 = 1/2`

` x = 1/2 - 3/4`

`x = -1/4`

TH2

` x + 3/4 = -1/2`

` x = -1/2 - 3/4`

` x =-5/4`

 

Đáp án:

 

Giải thích các bước giải:

+ ) |x| = 0

→ x = 0

+ ) |x| = 1,375

→ \(\left[ \begin{array}{l}x=1,375\\x=-1,375\end{array} \right.\) 

+ ) |x| = $\frac{1}{5}$ 

→ \(\left[ \begin{array}{l}x=\frac{1}{5}\\x=-\frac{1}{5}\end{array} \right.\) 

+ ) |x| = 3$\frac{1}{4}$ 

→ \(\left[ \begin{array}{l}x = 3\frac{1}{4} \\x=-(3\frac{1}{4}) \end{array} \right.\) 

+ ) | x - 1,5 | = 2

→ \(\left[ \begin{array}{l}x -1,5=2\\x-1,5=-2 \end{array} \right.\) 

→ \(\left[ \begin{array}{l}x =3,5\\x=-0,5\end{array} \right.\) 

+ ) | x + $\frac{3}{4}$ | - $\frac{1}{2}$ = 0

| x + $\frac{3}{4}$ | = $\frac{1}{2}$

→ \(\left[ \begin{array}{l}x + \frac{3}{4}=\frac{1}{2}\\x+\frac{3}{4}=-\frac{1}{2}\end{array} \right.\) 

→ \(\left[ \begin{array}{l}x =-\frac{1}{4}\\x=-\frac{5}{4}\end{array} \right.\)