1. Sửa đề: $26p$, $26e$, $30n$

$m_n=30.1,67.10^{-24}=5,01.10^{-23}(g)$

$m_p=26.1,67.10^{-24}=4,342.10^{-23}(g)$

$m_e=30.9,1.10^{-28}=2,73.10^{-26}(g)$

$\Rightarrow m_{Fe}=m_p+m_n+m_e=9,35.10^{-23}(g)$

2.

Trong $9,35.10^{-23}g$ sắt có $2,73.10^{-26}g$ electron.

$\Rightarrow 1000g$ sắt có:

$m_e=\dfrac{2,73.10^{-26}.1000}{9,35.10^{-23}}=0,292g$

1.tính M sắt ( g), mp,mn,me

$m_e=26.9,1.10^{-28}=2,366.10^{-26}(g)$

$m_p=26.1,67.10^{-24}=4,342.10^{-23}(g)$

$m_n=30.1,67.10^{-24}=5,01.10^{-23}(g)$

⇒m $Fe$=$m_p+m_e+m_n$≈$9,35.10^{-23}(g)$

-Tính Me có trong 1 kg ng tử sắt

$m_e=\dfrac{2,366.10^{-26}.1000}{9,35.10^{-23}}=0,253(g)$

---------------------Nguyễn Hoạt--------------------