Em tham khảo nha:

\(\begin{array}{l}
1)\\
{M_{F{e_2}{{(S{O_4})}_x}}} = 400 \Leftrightarrow 2{M_{Fe}} + x \times ({M_S} + 4{M_O}) = 400\\
 \Leftrightarrow 2 \times 56 + 96x = 400 \Rightarrow x = 3\\
 \Rightarrow CTHH:F{e_2}{(S{O_4})_3}\\
2)\\
{M_{F{e_x}{O_3}}} = 160 \Leftrightarrow x{M_{Fe}} + 3{M_O} = 160\\
 \Leftrightarrow 56x + 3 \times 16 = 160 \Rightarrow x = 2\\
 \Rightarrow CTHH:F{e_2}{O_3}\\
3)\\
{M_{A{l_2}{{(S{O_4})}_x}}} = 342 \Leftrightarrow 2{M_{Al}} + x \times ({M_S} + 4{M_O}) = 342\\
 \Leftrightarrow 2 \times 27 + 96x = 342 \Rightarrow x = 3\\
 \Rightarrow CTHH:A{l_2}{(S{O_4})_3}\\
4)\\
{M_{{K_2}{{(S{O_4})}_x}}} = 174 \Leftrightarrow 2{M_K} + x \times ({M_S} + 4{M_O}) = 174\\
 \Leftrightarrow 2 \times 39 + 96x = 174 \Rightarrow x = 1\\
 \Rightarrow CTHH:{K_2}S{O_4}\\
5)\\
{M_{C{a_x}{{(P{O_4})}_2}}} = 310 \Leftrightarrow x \times {M_{Ca}} + 2 \times ({M_P} + 4{M_O}) = 310\\
 \Leftrightarrow 40x + 190 = 310 \Rightarrow x = 3\\
 \Rightarrow CTHH:C{a_3}{(P{O_4})_2}
\end{array}\)

Đáp án:

Giải thích các bước giải: