Em tham khảo nha:

\(\begin{array}{l}
a)\\
{V_{hh}} = {V_{{N_2}}} + {V_{C{l_2}}} + {V_{{O_2}}} + {V_{{N_2}O}}\\
 \to {V_{hh}} = 26,88 + 16,8 + 17,92 + 25,2 = 86,8l\\
b)\\
{n_{{N_2}}} = \dfrac{V}{{22,4}} = \frac{{26,88}}{{22,4}} = 1,2\,mol\\
{n_{{O_2}}} = \dfrac{V}{{22,4}} = \frac{{16,8}}{{22,4}} = 0,75\,mol\\
{n_{C{l_2}}} = \dfrac{V}{{22,4}} = \frac{{17,92}}{{22,4}} = 0,8\,mol\\
{n_{{N_2}O}} = \dfrac{V}{{22,4}} = \frac{{25,2}}{{22,4}} = 1,125\,mol\\
{n_{hh}} = 1,2 + 0,75 + 0,8 + 1,125 = 3,875\,mol\\
c)\\
{m_{hh}} = {m_{{N_2}}} + {m_{C{l_2}}} + {m_{{O_2}}} + {m_{{N_2}O}}\\
 \Rightarrow {m_{hh}} = 1,2 \times 28 + 0,75 \times 32 + 0,8 \times 71 + 1,125 \times 44 = 163,9g\\
d)\\
{M_{hh}} = \dfrac{{{m_{hh}}}}{{{n_{hh}}}} = \frac{{163,9}}{{3,875}} = 42,3(g/mol)
\end{array}\)

Đáp án:

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