Em tham khảo nha:

\(\begin{array}{l}
19.2\\
{V_{C{O_2}}} = n \times 22,4 = 0,25 \times 22,4 = 5,6l\\
{V_{{O_2}}} = n \times 22,4 = 0,25 \times 22,4 = 5,6l\\
{n_{{N_2}}} = \dfrac{m}{M} = \dfrac{{21}}{{28}} = 0,75\,mol\\
{V_{{N_2}}} = n \times 22,4 = 0,75 \times 22,4 = 16,8l\\
{n_{C{O_2}}} = \dfrac{m}{M} = \dfrac{{8,8}}{{44}} = 0,2\,mol\\
{V_{C{O_2}}} = n \times 22,4 = 0,2 \times 22,4 = 4,48l\\
{n_{{H_2}}} = \dfrac{{9 \times {{10}^{23}}}}{{6 \times {{10}^{23}}}} = 1,5\,mol\\
{V_{{H_2}}} = n \times 22,4 = 1,5 \times 22,4 = 33,6l\\
{n_{CO}} = \dfrac{{0,3 \times {{10}^{23}}}}{{6 \times {{10}^{23}}}} = 0,05\,mol\\
{V_{CO}} = n \times 22,4 = 0,05 \times 22,4 = 1,12l\\
19.6\\
n = \dfrac{V}{{22,4}} = \frac{{5,6}}{{22,4}} = 0,25\,mol\\
a){m_{C{O_2}}} = n \times M = 0,25 \times 44 = 11g\\
b)\,{m_{C{H_4}}} = n \times M = 0,25 \times 16 = 4g\\
c)\,{m_{{O_2}}} = n \times M = 0,25 \times 32 = 8g\\
d)\,{m_{{N_2}}} = n \times M = 0,25 \times 28 = 7g\\
e)\,{m_{C{l_2}}} = n \times M = 0,25 \times 71 = 17,75g
\end{array}\)