Đáp án:k bic đk nha

 

Giải thích các bước giải:

a)PTHH: R+2HCl->RCl2+H2

nH2=3,36/22,4=0,15(mol)

=>MR=m/n=3,6/0,15=24(g/mol)

=>R là magie(mg)

=>PTHH:Mg+2HCl->MgCl2+H2

b)mHCl=0,3*36,5=10,95(g)

=>C%ddHCl=10,95*100/150=7,3%

c)mH2=0,15*2=0.3(g)

AD ĐLBTKL:

mddMgCl2=mMg+mđHCl-mH2=3,6+150-0,3=153,3g

mMgCl2=0,15*95=14,25g

=>C%ddMgCl2=14,25/153,3*100=9,29%

 

Em tham khảo nha :

\(\begin{array}{l}
a)\\
R + 2HCl \to RC{l_2} + {H_2}\\
{n_{{H_2}}} = \dfrac{{3,36}}{{22,4}} = 0,15mol\\
{n_R} = {n_{{H_2}}} = 0,15mol\\
{M_R} = \dfrac{{3,6}}{{0,15}} = 24dvC\\
R:Magie(Mg)\\
b)\\
{n_{HCl}} = 2{n_{{H_2}}} = 0,3mol\\
{m_{HCl}} = 0,3 \times 36,5 = 10,95g\\
C{\% _{HCl}} = \dfrac{{10,95}}{{150}} \times 100\%  = 7,3\% \\
c)\\
{n_{MgC{l_2}}} = {n_{{H_2}}} = 0,15mol\\
{m_{MgC{l_2}}} = 0,15 \times 95 = 14,25g\\
C{\% _{MgC{l_2}}} = \dfrac{{14,25}}{{3,6 + 150 - 0,3}} \times 100\%  = 9,3\% 
\end{array}\)