Đáp án + Giải thích các bước giải:

$a)$

$C_{12}H_{22}O_{11}+H_2O\xrightarrow{t^o,H^+}C_6H_{12}O_6+C_6H_{12}O_6$

$C_6H_{12}O_6\xrightarrow{t^o,enzim}2C_2H_5OH+2CO_2$

$b)$

$C_6H_{12}O_6\xrightarrow{t^o,enzim}2C_2H_5OH+2CO_2$

$C_2H_5OH+O_2\xrightarrow{men}CH_3COOH+H_2O$

$2CH_3COOH+Ca\to (CH_3COO)_2Ca+H_2$

$(CH_3COO)_2Ca+H_2SO_4\to CaSO_4+2CH_3COOH$

$CH_3COOH+C_2H_5OH\buildrel{{t^o,H_2SO_4}}\over\rightleftharpoons CH_3COOC_2H_5+H_2O$

Em tham khảo nha:

\(\begin{array}{l}
a)\\
{C_{12}}{H_{22}}{O_{11}} + {H_2}O \xrightarrow{xt,t^0} {C_6}{H_{12}}{O_6} + {C_6}{H_{12}}{O_6}\\
{C_6}{H_{12}}{O_6} \xrightarrow{\text{ lên men }}  2{C_2}{H_5}OH + 2C{O_2}\\
b)\\
{C_6}{H_{12}}{O_6} \xrightarrow{\text{ lên men }}  2{C_2}{H_5}OH + 2C{O_2}\\
{C_2}{H_5}OH + {O_2} \xrightarrow{\text{  men giấm }}  C{H_3}COOH + {H_2}O\\
2C{H_3}COOH + Ca \to {(C{H_3}COO)_2}Ca + {H_2}\\
{(C{H_3}COO)_2}Ca + {H_2}S{O_4} \to 2C{H_3}COOH + CaS{O_4}\\
C{H_3}COOH + {C_2}{H_5}OH \rightleftarrows C{H_3}COO{C_2}{H_5} + {H_2}O
\end{array}\)