Đáp án + Giải thích các bước giải:

$b\big)$

$CaC_2+2H_2O\to Ca(OH)_2+C_2H_2$

$C_2H_2+H_2\xrightarrow{t^o,Pd/PbCO_3}C_2H_4$

$C_2H_4+H_2O\xrightarrow{t^o,axit}C_2H_5OH$

$C_2H_5OH+O_2\xrightarrow{men\,giấm}CH_3COOH+H_2O$

$CH_3COOH+C_2H_5OH\buildrel{{t^o,H_2SO_{4(đ)}}}\over\rightleftharpoons CH_3COOC_2H_5+H_2O$

$CH_3COOC_2H_5+NaOH\to CH_3COONa+C_2H_5OH$

$2CH_3COONa+H_2SO_4\to 2CH_3COOH+Na_2SO_4$

$CH_3COOH+2O_2\xrightarrow{t^o}2CO_2+2H_2O$

$CO_2+Ca(OH)_2\to CaCO_3+H_2O$

$CaCO_3+2CH_3COOH\to (CH_3COO)_2Ca+CO_2+H_2O$

$(CH_3COO)_2Ca+H_2SO_4\to CaSO_4+2CH_3COOH$

$2CH_3COOH+Fe\to (CH_3COO)_2Fe+H_2$

$C+2H_2\xrightarrow{t^o,xt}CH_4$

$CH_4+Cl_2\xrightarrow{as}CH_3Cl+HCl$

Đáp án+ Giải thích các bước giải:

$b)$

$CaC_2 + 2H_2O$ `->` $C_2H_2 + Ca(OH)_2$

$C_2H_2 + H_2$ $\xrightarrow{Pd , t^o}$ $C_2H_4$

$C_2H_4 + H_2O$ $\xrightarrow[Axit]{t^o}$ $C_2H_5OH$

$C_2H_5OH + O_2$ $\xrightarrow{\text{Men giấm}}$ $CH_3COOH + H_2O$

$CH_3COOH + C_2H_5OH$ $\buildrel{{H_2SO_4(đ) , t^o}}\over\rightleftharpoons$ $CH_3COOC_2H_5 + H_2O$

$CH_3COOC_2H_5 + NaOH$ $\xrightarrow{ t^o}$ $CH_3COONa + C_2H_5OH$

$CH_3COONa + HCl$ `->` $CH_3COOH + NaCl$

$CH_3COOH + 2O_2$ $\xrightarrow{ t^o}$ $2CO_2 + 2H_2O$

$CO_2 + Ca(OH)_2$ `->` $CaCO_3 + H_2O$

$CaCO_3 + 2CH_3COOH$ `->` $(CH_3COO)_2Ca + CO_2 + H_2O$

$(CH_3COO)_2Ca + H_2SO_4$ `->` $2CH_3COOH + CaSO_4$

$2CH_3COOH + Mg$ `->` $CH_3COO)_2Mg + H_2$

$2H_2 + C$ $\xrightarrow{ xt , t^o}$ $CH_4$

$CH_4 + Cl_2$ $\xrightarrow{as}$  $CH_3Cl + HCl$