Đáp án + Giải thích các bước giải:

$\rm \mathop{S}\limits^{0}+H_2\xrightarrow{t^o}H_2\mathop{S}\limits^{-2}$

$\rm 2H_2\mathop{S}\limits^{-2}+O_2\xrightarrow{t^o}2\mathop{S}\limits^{0}+2H_2O$

$\rm \mathop{S}\limits^{0}+O_2\xrightarrow{t^o}\mathop{S}\limits^{+4}O_2$

$\rm 2\mathop{S}\limits^{+4}O_2+O_2+2H_2O\to 2H_2\mathop{S}\limits^{+6}O_4$

$\rm Cu+2H_2\mathop{S}\limits^{+6}O_{4(đ)}\xrightarrow{t^o}CuSO_4+\mathop{S}\limits^{+4}O_2+2H_2O$

$2H_2S+\mathop{S}\limits^{+4}O_2\to 3\mathop{S}\limits^{0}+2H_2O$

$$------------------------$$

$\rm 3\mathop{Cl_2}\limits^{0}+6KOH\xrightarrow{t^o}5KCl+K\mathop{Cl}\limits^{+5}O_3+3H_2O$

$\rm 2K\mathop{Cl}\limits^{+5}O_3\xrightarrow[MnO_2]{t^o}2K\mathop{Cl}\limits^{-1}+3O_2$

$\rm 2K\mathop{Cl}\limits^{-1}\xrightarrow{đpnc}2K+\mathop{Cl_2}\limits^{0}$

$\rm \mathop{Cl_2}\limits^{0}+H_2O\leftrightharpoons H\mathop{Cl}\limits^{+1}O+HCl$

Đáp án + Giải thích các bước giải:

 $S + H_2 \xrightarrow{t^o} H_2S$
$2H_2S + SO_2 \longrightarrow 3S \downarrow + 2H_2O$

$S + O_2 \xrightarrow{t^o} SO_2$

$SO_2 + Br_2 + H_2O \longrightarrow H_2SO_4 + HBr$

$2H_2SO_{4(đ,n)} + Cu \longrightarrow CuSO_4 + SO_2 \uparrow + 2H_2O$

$2H_2S + SO_2 \longrightarrow 3S \downarrow + 2H_2O$

$-------------------$

$3Cl_2 + 6NaOH \xrightarrow{t^o} 5NaCl + NaClO_3 + 3H_2O$

$NaClO_3 + 6HCl \longrightarrow NaCl + 3Cl_2 \uparrow + 3H_2O$

$2NaCl + 2H_2O \xrightarrow[cmn]{đpdd} 2NaOH + H_2 \uparrow + Cl_2 \uparrow$

$Cl_2 + H_2O \rightleftharpoons HCl + HClO$