Đáp án+Giải thích các bước giải:

$\text{a)}$

$\text{C%$NaCl$=$\dfrac{100S}{100 + S}$=$\dfrac{100.36}{100 + 36}$= 26,47%}$

$\text{b)}$

$\text{$m_{dd}$=$m_{ct}$ + $m_{dm}$=50 + 150= 200 (g)}$

$\text{→ C%=$\dfrac{m_{ct}}{m_{dd}}$ × 100%=$\dfrac{50}{200}$ × 100%= 25%}$

$\text{d)}$

$\text{Đổi: 100ml = 0,1}$ `l`

$\text{$n_{CuSO_{4}}$=$\dfrac{m}{M}$=$\dfrac{32}{160}$= 0,2 (mol)}$

$\text{→ $C_{M_{CuSO_{4}}}$=$\dfrac{n}{V}$=$\dfrac{0,2}{0,1}$= 2 (M)}$

$\text{e)}$

$\text{$n_{NaCl}$=$C_{M}$.V=0,5.1= 0,5 (mol)}$

$\text{f)}$

$\text{Đổi: 500ml = 0,5}$ `l`

$\text{$n_{KCl}$=$\dfrac{m}{M}$=$\dfrac{7,45}{74,5}$= 0,1 (mol)}$

$\text{→ $C_{M_{KCl}}$=$\dfrac{n}{V}$=$\dfrac{0,1}{0,5}$= 0,2 (M)}$