Đáp án:

$\downarrow$

Giải thích các bước giải:

* `500ml=0,5l`

* `n_{HCl}=0,5xx0,2=0,1(mol)`

`a,` `-` PTHH:    `Zn+2HCl->ZnCl_2+H_2`

`->n_{Zn}=1/2n_{HCl}=0,05(mol)`

`->m_{Zn}=0,05xx65=3,25(gam)`

`b,` * PTHH `->n_{ZnCl_2}=n_{Zn}=0,05(mol)`

`->C_(M_{ZnCl_2})=(0,05)/(0,5) = 0,1M`

$\text{#Kudo}$

Em tham khảo nha:

\(\begin{array}{l}
a)\\
500ml = 0,5l\\
{n_{HCl}} = {C_M} \times V = 0,2 \times 0,5 = 0,1\,mol\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
{n_{Zn}} = \dfrac{{{n_{HCl}}}}{2} = \dfrac{{0,1}}{2} = 0,05\,mol\\
{m_{Zn}} = n \times M = 0,05 \times 65 = 3,25g\\
b)\\
{n_{ZnC{l_2}}} = {n_{Zn}} = 0,05\,mol\\
{C_M}ZnC{l_2} = \dfrac{n}{V} = \dfrac{{0,05}}{{0,5}} = 0,1M
\end{array}\)