Em tham khảo nha ;

\(\begin{array}{l}
a)\\
Mn{O_2} + 4HCl \to MnC{l_2} + C{l_2} + 2{H_2}O\\
C{l_2} + {H_2} \to 2HCl\\
2HCl + 2Na \to 2NaCl + {H_2}\\
2NaCl \xrightarrow{dpnc} C{l_2} + 2Na\\
C{l_2} + 2NaOH \to NaCl + NaClO + {H_2}O\\
b)\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
FeC{l_2} + 2NaOH \to Fe{(OH)_2} + 2NaCl\\
Fe{(OH)_2} + 2HCl \to FeC{l_2} + 2{H_2}O\\
2FeC{l_2} + C{l_2} \to 2FeC{l_3}\\
FeC{l_3} + 3AgN{O_3} \to Fe{(N{O_3})_3} + 3AgCl\\
c)\\
2KMn{O_4} + 16HCl \to 5C{l_2} + 2KCl + 2MnC{l_2} + 8{H_2}O\\
C{l_2} + 2K \to 2KCl\\
2KCl + 2{H_2}O \xrightarrow{dpcmn} C{l_2} + {H_2} + 2KOH\\
C{l_2} + {H_2}O \to HClO + HCl\\
HClO + NaOH \to NaClO + {H_2}O\\
NaClO + 2HCl \to C{l_2} + {H_2}O + NaCl\\
2NaCl \xrightarrow{dpnc} C{l_2} + 2Na\\
3C{l_2} + 2Fe \to 2FeC{l_3}
\end{array}\)

 

Đáp án:

 

Giải thích các bước giải:

a) MnO2 + 4HCl --> MnCL2 + Cl2 + H2O

Cl2 + H2 = đk ánh sáng 2HCl

HCl + NaOH = NaCl + H2O 

NaCl--> đpnc Cl2 + Na

Cl2 + NaOH = NaCl + NaClO + H2O

b) Fe + HCl--> FeCl2 + H2

FeCl2 + H2O= Fe(OH)2 + HCl

Fe(OH)2 + NaCl = NaOH + FeCl2

FeCl2 + Cl2 = FeCL3

FeCl3 + AgNO3 = Fe(NO3)3 + AgCL 

c) KMnO4 + HCl = KCl + MnCL2 + Cl2 + H2O
CL2 + K = KCl

KCl = đpnc Cl2 + K

CL2 + H2O = HCl + HClO

HClo + NaOH = NaClO + H2O

NaCLO = NaCL + O2

NaCl = đpnc Na + Cl2

CL2 + Fe = FeCL3