Đáp án:

\(\begin{array}{l}
\% {V_{{C_2}{H_2}}} = 33,67\% \\
\% {V_{{C_3}{H_8}}} = 25\% \\
\% {V_{{C_2}{H_4}}} = 41,33\% \\
\% {m_{{C_3}{H_8}}} = 35,11\% \\
\% {m_{{C_2}{H_4}}} = 36,94\% \\
\% {m_{{C_2}{H_2}}} = 27,95\% 
\end{array}\)

Giải thích các bước giải:

\(\begin{array}{l}
a)\\
{C_2}{H_4} + B{r_2} \to {C_2}{H_4}B{r_2}\\
{C_2}{H_2} + 2B{r_2} \to {C_2}{H_2}B{r_4}\\
{C_2}{H_2} + 2AgN{O_3} + 2N{H_3} \to A{g_2}{C_2} + 2N{H_4}N{O_3}\\
b)\\
{n_{A{g_2}{C_2}}} = \dfrac{{48,48}}{{240}} = 0,202\,mol\\
{n_{{C_2}{H_2}}} = {n_{A{g_2}{C_2}}} = 0,202\,mol\\
{V_{{C_3}{H_8}}} = {V_k} = 3,36l\\
\% {V_{{C_2}{H_2}}} = \dfrac{{0,202 \times 22,4}}{{13,44}} \times 100\%  = 33,67\% \\
\% {V_{{C_3}{H_8}}} = \dfrac{{3,36}}{{13,44}} \times 100\%  = 25\% \\
\% {V_{{C_2}{H_4}}} = 100 - 25 - 33,67 = 41,33\% \\
{n_{{C_2}{H_4}}} = \dfrac{{13,44 - 3,36 - 0,202 \times 22,4}}{{22,4}} = 0,248\,mol\\
\% {m_{{C_3}{H_8}}} = \dfrac{{0,15 \times 44}}{{0,15 \times 44 + 0,202 \times 26 + 0,248 \times 28}} \times 100\%  = 35,11\% \\
\% {m_{{C_2}{H_4}}} = \dfrac{{0,248 \times 28}}{{0,15 \times 44 + 0,202 \times 26 + 0,248 \times 28}} \times 100\%  = 36,94\% \\
\% {m_{{C_2}{H_2}}} = 100 - 36,94 - 35,11 = 27,95\% 
\end{array}\)