\(Anot( + )\)

\(n_{NaCl}^{} = 0,6.0,6 = 0,36\;{\text{mol}}\)

\(2C{l^ - } \to Cl_2^{} + 2e\)

\(\;{\text{0}}{\text{,36    0}}{\text{,18   0}}{\text{,36}}\)

\({\text{n}}_{O_2^{}}^{} = 0,3 - 0,18 = 0,12\;{\text{mol}}\)

\(2H_2^{}O \to 4{H^ + } + O_2^{} + 4e\)

\({\text{                        0}}{\text{,12  0}}{\text{,48}}\)

\({\text{Trong thoi gian t mol thi n}}_e^{} = 0,48 + 0,36 = 0,84\;{\text{mol}}\)

\({\text{Trong thoi gian 2t mol thi n}}_e^{} = 0,84.2 = 1,68\;{\text{mol}}\)

\({\text{o anot so mol H}}_2^{}O{\text{ sinh ra O}}_2^{}\;{\text{la}}\)

\(2C{l^ - } \to Cl_2^{} + 2e\)

\(\;{\text{0}}{\text{,36    0}}{\text{,18   0}}{\text{,36}}\)

\(2H_2^{}O \to 4{H^ + } + O_2^{} + 4e\)

\({\text{                        0}}{\text{,33  1}}{\text{,32}}\)

\({\text{V}}_{H_2^{}(O{\text{ catot)}}}^{} = 0,85 - 0,33 - 0,18 = 0,34\;{\text{mol}}\)

\(Catot:H_2^{}O + 2e \to H_2^{} + O{H^ - }\)

\({\text{                    0}}{\text{,68    0}}{\text{,34}}\)

\(n_{e_{KL}^{}}^{} = 1,68 - 0,68 = 1\;{\text{mol}}\)

\(M_{tinhthe}^{} = \frac{{125}}{{1/n}}\)

\({\text{Bien luan tinh the X la n  =  2}} \to {\text{X = 250g/mol ; X la CuSO}}_4^{}.5H_2^{}O\)

\(m = \frac{{0,84}}{2}.64 = 26,88g\)